As we know that initial speed of projection is given as
[tex]v_i = 50 m/s[/tex]
angle of projection is given as
[tex]\theta = 36.9 degree[/tex]
now we have
[tex]v_{ix} = 50 cos36.9 = 40 m/s[/tex]
[tex]v_{iy} = 50 sin36.9 = 30 m/s[/tex]
now we will have
[tex]a_x = 0 m/s^2[/tex]
[tex]a_y = -10.0 m/s^2[/tex]
so here at all time instant speed in x direction remains the same
[tex]v_x = 40 m/s[/tex]
while in y direction we will have
[tex]v_y = v_{iy} + at[/tex]
[tex]v_y = 30 - 10 t[/tex]
now between t = 0 to t = 6 s we have
[tex]v_y = 30 m/s, v_y = 20 m/s, v_y = 10 m/s, v_y = 0 m/s, v_y = -10 m/s, v_y = -20 m/s, v_y = -30 m/s[/tex]
now we have
[tex]x = v_x t[/tex]
[tex]x = 40 t[/tex]
now between t = 0 to t = 6 s we have
[tex]x = 0, x = 40 m, x = 80 m, x = 120 m, x = 160 m, x = 200 m, x=240 m[/tex]
Now for y component we have
[tex]y = v_{iy} t + \frac{1}{2}at^2[/tex]
[tex]y = 30(t) - 5 t^2[/tex]
[tex]y = 0 m, y = 25 m, y = 40 m, y = 45 m, y = 40 m, y = 25 m, y = 0[/tex]
