Answer:
Step-by-step explanation:
Let the distance the slower hiker travels=d,
the distance the faster hiker travels=15-d (Since, the sum of the distances they walk is 15mi).
Let the speed of the slower hiker in mi/hr=s,
the speed of the faster hiker=s+0.5
Now, equation for the slow hiker:
[tex]d=s(2)[/tex]
[tex]d=2s[/tex] (1)
and equation for the faster hiker:
[tex]15-d=(s+0.5)(2)[/tex]
[tex]15-d=2s+1[/tex]
[tex]2s+d=14[/tex] (2)
Now, substituting the equation (1) in equation (2),
[tex]2s+2s=14[/tex]
[tex]4s=14[/tex]
[tex]s=3.5[/tex]
and [tex]s+0.5=3.5+0.5=4.0[/tex]
The speed of the slower hiker is [tex]3.5\frac{mi}{hr}[/tex]and The speed of the faster hiker is [tex]4\frac{mi}{hr}[/tex].
