Respuesta :
Scenario 1 :
The gray bodied fly is heterozygous, which means that the gray color is dominant (G), while the black color (g) of the body is recessive. Hence, the genotype of the parents and the offspring will be:
Parent 1: Gg
Parent 2: gg
Offspring: Gg, Gg, gg, gg
Scenario 2 :
The condition that appears is a heterozygous condition is dominant, and hence, the dominant phenotype in this question is 'gray bodies'.
Scenario 3 :
The homozygous long winged fly (L) and the homozygous vestigial winged fly (l) will have the following genotypes:
Parent 1: LL
Parent 2: ll
Offspring: Ll, Ll, Ll, Ll
Scenario 4:
The long-winged phenotype is dominant as it is visible in a heterozygous condition. Hence, a cross between a homozygous long-winged fly and a heterozygous long-winged fly will result in 100% long-winged flies.
Scenario 5:
The long-winged allele is dominant (L) over the vestigial/short -wing allele. Therefore, a cross between a heterozygous long-winged fly and an heterozygous long-winged fly will result in the following of long-winged offspring to the short-winged offspring : '3:1'
Scenario 6:
The gray body color allele (G) is dominant over the black body color allele (g). Hence, in order to produce offsprings out of which 50% are homozygous gray bodies, and 50% are heterozygous gray bodied, the allele of the parents must be:
Parent 1: GG
Parent 2: Gg
Scenario 7:
The long-winged allele is dominant (L) over the vestigial/short -wing allele (l). Hence in order to produce offspring out of which 50% are heterozygous long-winged and 50% are vestigial-winged, the genetotypes of the parents must be :
Parent 1: ll
Parent 2: Ll
Scenario 8:
The offsprings of a homozygous gray bodied fly (GG) and a homozygous black bodied fly (gg) will be heterozygous gray bodied flies (Gg). Hence, the phenotype of the parents is:
One will have gary body and other will have black body.
Scenario 9:
The long-winged allele is dominant (L) over the vestigial/short -wing allele (l). Hence in order to produce offspring that are all vestigial winged, the genotype of the parents should be ll and ll. Hence, the phenotype of the parents will be:
Both parents will have vestigial wings.
Scenario 10:
The gray body color allele (G) is dominant over the black body color allele (g). Hence, in order to produce offsprings that are black bodied, the genotype of the parents should be gg and gg. Hence, the phenotype of the parents will be:
Both will be black bodied.





Answer:
Scenaro 1:
Answer:
Gg * gg
Gg , Gg , gg , gg
Parent 1 :Gg
Parent 2: gg
Scenario 2:
Answer:
Gg * Gg
GG , Gg , Gg , gg
GG,Gg,Gg = will be gray (75%).
gg = will black (25%).
Gray will be dominent.
Scenario 3:
Answer:
LL: Homozygous long winged fly
ll: Homozygos vestigial winged fly
LL * ll
Ll , Ll , Ll , Ll
All offsprings will be hetrozygous long winged
Scenario 4:
Answer:
Homozygous long winged fly : LL
Hetrozygous long winged fly : Ll
LL * Ll
LL , Ll , LL , Ll
100% long winged flies.
Scenario 5:
Answer:
Hetrozygous long winged fly :Ll
Ll * Ll
LL , Ll , LL ,ll
3 : 1
long winged : vestigial winged.
Scenario 6:
Answer:
GG * Gg
GG , Gg , GG ,Gg
GG 50% homozygous grey bodies.
Gg 50% hetrozygous grey bodies.
Scenario 7:
Answer:
Ll * ll
Ll , Ll , ll , ll
Ll :long winged .
ll : vestigial winged.
Scenario 8:
Answer:
GG * gg
Gg , Gg , Gg , Gg
One parent will have gray body GG.
Second parent will have black body gg.
Scenario 9:
Answer:
ll * ll
ll , ll , ll , ll
Both parents will have vestigial wings .
Scenario 10:
Answer:
gg * gg
gg , gg ,gg , gg
Both parents will have black bodies.