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The combustion of 45.0 g of methane (natural gas) releases 2498 kJ of heat energy. What amount of energy (in kilocalories) would be released for the combustion of 0.440 oz (ounces) of methane?

Respuesta :

Answer: 166.13 kcal

Explanation:

1 ounce = 28.35 g

0.440 ounce=[tex]\frac{28.35}{1}\times 0.440=12.47g[/tex]

Given: 45.0 g of methane releases= 2498 kJ of heat energy

Thus 12.47 g of methane releases=[tex]frac {2498}{45}\times 12.47=692.2kJ[/tex] of heat energy

1 kJ =0.24 kcal

692.2 kJ=[tex]\frac {0.24}{1}\times 692.2=166.13kcal[/tex]

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