Respuesta :

MrGumby

Answer:

The correct answer is b) 1100 adults and 1400 students.

Step-by-step explanation:

To find this, set up a system of equations in which x is the number of students who attend and y is the number of adults who attend.

First start by creating an equation for money made.

5x + 10y = 18,000

Now write an equation for the amount that attend.

x + y = 2,500

Now multiply the bottom equation by -5 and add the equations together.

-5x - 5y = -12,500

5x + 10y = 18,000

5y = 5,500

y = 1,100

Since this is the number of adults, we can plug into an original equation to find the number of students.

x + y = 2,500

x + 1,100 = 2,500

x = 1,400

znk

Answer:

1100 adults and 1400 students  

Step-by-step explanation:

Let S = students and A = adults.

We have two conditions.

(1)               5S + 10A = 18 000

(2)                    S + A = 2500     Subtract A from each side

(3)                          S = 2500 – A     Substitute (3) into (1)

 5(2500 – A) + 10A = 18 000     Remove parentheses

12 500 – 5A + 10 A = 18 000     Combine like terms

           12 500 + 5A = 18 000     Subtract 12 500 from each side

                           5A = 5500        Divide each side by 6

(4)                          A = 1100         Substitute (4) into (2)

                  S + 1100 = 2500         Subtract 1100 from each side

                             S = 1400

There were 1100 adults and 1400 students.

Check:

5 × 1400 + 10 × 1100 = 18 000         1400 + 1100 = 2500

       7 000 + 11 000 = 18 000                   2500 = 2500

                   1 8 000 = 18 000


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