An isosceles triangle has two sides of equal length, a, and a base, b. The perimeter of the triangle is 15.7 inches, so the equation to solve is 2a + b = 15.7. If we recall that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side, which lengths make sense for possible values of b? Select two options. –2 in. 0 in. 0.5 in. 2 in. 7.9 in.

Respuesta :

Answer:


Step-by-step explanation:

Let the two same sides of an isosceles triangle be a and the base be b, then Perimeter of triangle=Sum of all the sides=15.7 inches

⇒a+a+b=15.7

⇒2a+b=15.7                                (1)

Also, we know that  the sum of the lengths of any two sides of a triangle must be greater than the length of the third side, therefore

⇒a+a>b

⇒2a>b                                         (2)

From (1), the value of a will be:

a=[tex]\frac{15.7-b}{2}[/tex]

Therefore, equation (2) becomes

[tex]\frac{15.7-b}{2}>\frac{b}{2}[/tex]

⇒[tex]15.7>2b[/tex]

⇒[tex]7.85>b[/tex]

Thus, the possible value of b will be 7.9in


Answer:

The correct answers are : 0.5 inches and 2 inches.

Step-by-step explanation:

perimeter of isosceles triangle =15.7 inches

Length of two equal sides = a

Length of third side = b

Perimeter = 2a + b = 15.7 inches

Given that 'the sum of the lengths of any two sides of a triangle must be greater than the length of the third side'.

2a > b

If b = 0.5

2a +0.5 inch= 15.7

2a=15.7

2a > b (possible)

If b=2 inches

2a +2=15.7

2a = 13.7 inch

2a > 2 inches (possible)