Answer:
Option D is correct.
x y
0 5
1 10
2 20
Step-by-step explanation:
Given the equation: [tex]y = 5(2)^x[/tex] .....[1]
Here, x is the input variable and y is the output variable.
For x =0
Substitute in equation [1]; we have;
[tex]y = 5(2)^{0} = 5 \cdot 1= 5[/tex]
For x = 1
Substitute in equation [1]; we have;
[tex]y = 5(2)^{1} = 5 \cdot 2= 10[/tex]
For x =2
Substitute in equation [1]; we have;
[tex]y = 5(2)^{2} = 5 \cdot 4= 20[/tex]
Therefore, the table values which is correct for the equation [tex]y = 5(2)^x[/tex] is;
x y
0 5
1 10
2 20
