A semicircle and a quarter circle are attached to the sides of a rectangle as shown. What is the area of this figure? Use 3.14 for pi. Enter your answer in the box. Round only your final answer to the nearest whole number.

Answer:
109 cm^2
Step-by-step explanation:
We will find the area of the semi circle at the bottom.
The diameter is 12 so the radius is 6
A semicircle is 1/2 of a circle so it has 1/2 the area
A = pi r^2
A semicircle = 1/2 pi r^2
= 1/2 *pi *6^2
= 1/2 *3.14 *36
= 56.52
Next is the strip
It is rectangular with length 12 and width 2
A = l*w = 2*12 = 24
Finally we have the quarter circle
A quarter = 1/4 of the area of a circle
The radius is 6
A quarter = 1/4 pi r^2
=1/4 pi *6^2
= 1/4 *3.14 *36
= 28.26
Sum the areas together
A semi circle + A rectangle * A quarter circle
56.52 + 24+ 28.26
108.78 cm^2
Rounding to the nearest whole number
109 cm^2
Answer:
Step-by-step explanation:
solve it a lil diff - area of the figure is the same as that of a 12x2 rectangle plus 12-dia circle minus a quarter of that 12-dia circle.
rectangle area=12x2=24cm^2
full 12-dia circle area=pi(dia/2)^2=3.14(12/2)^2=3.14x36
quarter area of the 12-dia circle=3.14x36/4=3.14x9
total area=24+3.14x36-3.14x9
=108.78=109cm^2