Respuesta :
1. Solve.
This is a problem of inequalities. An inequality tells us that two values are different. Here we have a variable, so our aim is to find y letting it to the left of the sign. Therefore:
[tex]3y + 15 > -6 \\ \\ 3y>-6-15 \\ \\ 3y>-21 \\ \\ y>-\frac{21}{3} \\ \\ \boxed{y>-7}[/tex]
So y takes all the real number such that y is greater than -7.
2. Identify.
In this problem, we must identify the solution set of the inequality using the given replacement set. So this inequality is:
[tex]x < -4[/tex]
and the replacement set is:
[tex](-10, -4.3, -4, -3.9, 2, 6.5)[/tex]
Thus, from the given replacement, we must choose the numbers such that x < -4. Therefore, these numbers are -4.3 and -10. Finally, the solution set is:
[tex]\boxed{(-10, -4.3)}[/tex]
3. Solution.
We must find the solution to this problem. The graph of this problem is shown in the Figure below. So let's analyze each statement:
1. Number line from negative 10 to 10:
This line is in blue in the Figure below. See that it goes from -10 to 10.
2. Tick marks at every integer:
These are the marks in black.
3. Labels as negative ten, negative 5, 0, 5, and 10,
Those numbers are indicated in red.
4. Open red circle on negative 7.
You can see this circle on the figure.
5. red shading to the right of the red circle
You can see red shading to the left of the red circle.
Finally, our solution is indicated by the red shading and given that the red circle on -7 is open, then we use the sign > so our solution is:
[tex]y > -7 \ or: \\ \\ y+5>-7+5 \\ \\ \therefore \boxed{y + 5 > -2}[/tex]
Lastly, the correct option is:
(a) y + 5 > -2
4. Solution.
In this problem, Carlos wants to sent a gift basket to his grandmother. Deliver charges a fee in two ways:
1. A constant value ($4.45)
2. A value that depends on pound ($1.5 per pound)
So if x represents pound, then the fee can be found as follows:
4.45 + 1.05x
Since Carlos can only spend $15 or else on shipping, then we can say that:
[tex]4.45 + 1.05x \geq 15[/tex]
In other words, our correct option is:
(B) 4.45 + 1.05x Is greater then or equal to 15
