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ChevyChaseisslidingdownahillinatobogganatarateof5m/swhenhereaches and even steeper slope. If he accelerates at 2 m/s2 for the 5 m slope, how fast is he traveling when he reaches the bottom of the 5 m slope?

Respuesta :

Answer :   v = 6.7 m/s

Explanation :

It is given that :

Initial velocity, u = 5 m/s

Acceleration, [tex]a=2\ m/s^2[/tex]

Distance, s = 5 m

Using equation of motion:

[tex]v^2-u^2 =2as[/tex]

[tex]v^2-(5\ m/s)^2=2\times 2\ m/s^2\times 5\ m[/tex]

[tex]v^2=45\ m/s[/tex]

[tex]v=6.7\ m/s[/tex]

So, when he reaches the bottom of 5 m slope he is travelling with travelling with 6.7 m/s.

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