is the equation in the question written like the one in the bottom? Because for me to help you I must confirm what the equation looks like.
[tex]\frac{a-3}{2a^{2} -7a}[/tex] × [tex]\frac{4a-14}{a+3}[/tex]
Answer:
The term (2a-7) can be cancelled.
Step-by-step explanation:
We are given the following expression and we are to simplify it and see which terms get cancelled out:
[tex] \frac {a-3} {2a^2 - 7a } [/tex] × [tex] \frac { 4a - 14} {a + 3} [/tex]
Taking the common terms out to simplify it:
[tex]\frac{a-3}{a(2a-7)}[/tex] × [tex]\frac{2(2a-7)}{a+3}[/tex]
Here, the term [tex](2a-7)[/tex] get cancelled so we are left with:
[tex]\frac{2(a-3)}{a(a+3)}[/tex]
