Respuesta :
The reactions are
1)
[tex]Bi^{212} _{83} --> He^{4} _{2} +Tl^{208} _{81} ---> Pb^{208} _{82}+\beta ^{0} _{-1}[/tex]
In this reaction the Bismuth gives an alpha particle and followed by beta decay
2)
[tex]Bi^{212} _{83} + \beta ^{0}_{-1} -->He^{4} _{2}+Tl^{208} _{81} --->Pb^{208} _{82} \\[/tex]
In this reaction the Bismuth is undergoing beta bombardment followed by alpha decay.
3)
[tex]As^{216} _{85}--> He^{4} _{2}+As^{216} _{85} --->Pb^{216} _{85} +\beta ^{0}_{-1}[/tex]
This is not a reaction of Bismuth.
4)
[tex]Bi^{212} _{83} --->\beta ^{0}_{-1} +Tl^{208} _{81}--->Pb^{208} _{82}+He^{4} _{2}[/tex]
This is first beta elimination followed by alpha elimination.
Answer:
1)
Bi^{212} _{83} --> He^{4} _{2} +Tl^{208} _{81} ---> Pb^{208} _{82}+\beta ^{0} _{-1}
In this reaction the Bismuth gives an alpha particle and followed by beta decay
Explanation:
