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By Gay Lussacs law you can find the pressure. First both temperatures of Celsius must change to Kelvin by adding 273. Temperature one will be 308K and temperature 2 will be 258K
With this info, you can now find the pressure with Lussacs law
P1 = P2
— —
T1 T2
Pressure 1 is given which is 32 psi so just plug it all in and find P2
32 = x
—— ——
308 258
308x = 8256 (Cross multiply)
X = 26.8 (divide both sides by 308)
Answer is 26.8 PSI
This makes sense because as temperature increases pressure increases, as well as when temperature decreases, pressure decreases. Since it’s a colder day the pressure will be lower.
With this info, you can now find the pressure with Lussacs law
P1 = P2
— —
T1 T2
Pressure 1 is given which is 32 psi so just plug it all in and find P2
32 = x
—— ——
308 258
308x = 8256 (Cross multiply)
X = 26.8 (divide both sides by 308)
Answer is 26.8 PSI
This makes sense because as temperature increases pressure increases, as well as when temperature decreases, pressure decreases. Since it’s a colder day the pressure will be lower.
Considering the Gay- Lussac's Law, the pressure on a cold winter day is 26.80 psi.
Gay-Lussac's law is one of the gas laws, which establishes the relationship between the temperature and the pressure of a gas when the volume is constant.
This law states that the pressure of the gas is directly proportional to its temperature. In other words, if the temperature increases, the pressure will increase, while if the temperature decreases, the pressure will decrease.
Gay-Lussac's law can be expressed mathematically as follows:
[tex]\frac{P}{T}=k[/tex]
Where P = pressure, T = temperature, k = Constant
This law indicates that the quotient between pressure and temperature is constant.
Studying two different states, an initial state 1 and a final state 2, it is satisfied:
[tex]\frac{P1}{T1}=\frac{P2}{T2}[/tex]
In this case, you know:
- P1= 32 psi
- T1= 35 C= 308 K (being 0 C= 273 K)
- P2= ?
- T2= -15 C= 258 K
Replacing:
[tex]\frac{32 psi}{308 K}=\frac{P2}{258 K}[/tex]
Solving:
[tex]\frac{32 psi}{308 K}x258 K=P2[/tex]
P2= 26.80 psi
Finally, the pressure on a cold winter day is 26.80 psi.
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