Answer:
[tex](14x+21y)(6ab-3a)=84abx+126aby-42ax-63ay[/tex]
Step-by-step explanation:
Given : Two expression [tex](14x+21y)[/tex] and [tex](6ab-3a)[/tex]
To write : A product of 2 binomials and a monomial of the given expression
Solution :
To find the product of the given expression we have to first open the parenthesis and after opening we have to multiply each term of first expression with each term of another expression to get the result.
Step 1 - Write as a product
[tex](14x+21y)(6ab-3a)[/tex]
Step 2- Multiply term by term
[tex]14x(6ab)+21y(6ab)+(-3a)14x+21y(-3a)[/tex]
Step 3- Solve the expression
[tex]84abx+126aby-42ax-63ay[/tex]
Therefore, The required product is
[tex](14x+21y)(6ab-3a)=84abx+126aby-42ax-63ay[/tex]
