Respuesta :
Answer: There are [tex]3.25188\times 10^{23}[/tex] ammonium ions and [tex]1.62594\times 10^{23}[/tex] sulfate ions in the given amount of ammonium sulfate.
Explanation:
We are given 0.270 moles of ammonium sulfate and we need to find the number of ammonium and sulfate ions in it. The equation for the ionization of ammonium sulfate is given by the reaction:
[tex](NH_4)_2SO_4\rightarrow 2NH_4^++SO_4^{2-}[/tex]
By Stoichiometry,
1 mole of ammonium ions dissociates into 2 moles of ammonium ions and 1 mole of sulfate ion.
According to the mole concept:
1 mole of an ionic compound contains [tex]6.022\times 10^{23}[/tex] number of ions.
Hence, 0.270 mole of ammonium sulfate will contain [tex]0.270\times 2\times 6.022\times 10^{23}=3.25188\times 10^{23}[/tex] number of ammonium ions and [tex]0.270\times 1\times 6.022\times 10^{23}=1.62594\times 10^{23}[/tex] number of sulfate ions.
Hence, there are [tex]3.25188\times 10^{23}[/tex] ammonium ions and [tex]1.62594\times 10^{23}[/tex] sulfate ions in the given amount of ammonium sulfate.
