Can someone help me with these?

Solve each system of equations. Check each answer algebraically.
11. -­6x + 3y = 33
-­4x + y = 16
12. 2y = 5x ­-1
x + y = -­1
13. x + y + z = -­1
2x + 4y + z = 1
x + 2y ­- 3z = ­-3

Respuesta :

QUESTION 12

The given equations are;

[tex]-6x+3y=33...(1)[/tex] and [tex]-4x+y=14...(2)[/tex]

Make y the subject in equation (2).

[tex]y=4x+16..(3)[/tex]

We put this equation (3) into equation (1) to get;

[tex]-6x+3(4x+16)=33[/tex]

Expand;

[tex]-6x+12x+48=33[/tex]

[tex]6x=33-48[/tex]

[tex]6x=-15[/tex]

[tex]x=-\frac{5}{2}[/tex]

Put [tex]x=-\frac{5}{2}[/tex] into equation (3)

[tex]y=4(\frac{-5}{2})+16[/tex]

[tex]y=-10+16=6[/tex]

[tex]x=-\frac{5}{2},y=6[/tex]

QUESTION 12

The given equations are

[tex]2y=5x-1...(1)[/tex]

and

[tex]x+y=-1...(2)[/tex]

Make y the subject in equation (2)

[tex]y=-x-1...(3)[/tex]

Put equation (3) into (1)

[tex]2(-x-1)=5x-1[/tex]

[tex]-2x-2=5x-1[/tex]

[tex]-2+1=5x+2x[/tex]

[tex]7x=-1[/tex]

[tex]x=-\frac{1}{7}[/tex]

Put [tex]x=-\frac{1}{7}[/tex] into equation (3).

[tex]y=--\frac{1}{7}-1=-\frac{6}{7}[/tex]

QUESTION 13

The given equations are

[tex]x+y+z=-1...(1)[/tex]

[tex]2x+4y+z=1...(2)[/tex]

[tex]x+2y-3z=-3...(3)[/tex]

Make x the subject in equation (3).

[tex]x=3z-2y-3...(4)[/tex]

Put equation (4) into equation (1)

[tex]3z-2y-3+y+z=-1[/tex]

[tex]4z-y=2...(5)[/tex]

Put equation (4) into equation (2)

[tex]2(3z-2y-3)+4y+z=1[/tex]

[tex]6z-4y-6+4y+z=1[/tex]

[tex]7z=7[/tex]

[tex]z=1[/tex]

Put z=1 in equation (5)

[tex]4(1)-y=2[/tex]

[tex]y=4-2[/tex]

[tex]y=2[/tex]

Put y=2 and z=1 into equation(4)

[tex]x=3(1)-2(2)-3[/tex]

[tex]x=-4[/tex]