Respuesta :

chem1014
This is the only real root because roots are x-intercepts and there's only one x-intercept. Sometimes there would be three roots for a third degree polynomial but in this case it doesn't. The other roots are imaginary or complex numbers. So the only rational root is -1.653.
Ver imagen chem1014
Cricetus

Answer:

[tex]±\frac{1}{1} , ±\frac{1}{11} , ±\frac{5}{1} , ±\frac{5}{11}[/tex]

Step-by-step explanation:

If P(x) is a polynomial and we have to find all the potential rational roots of P(x) , we take all the possible ratios of the factors of "leading coefficient and the "constant term".

If [tex]P(x)=a_nx^n+a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+a_{n-3}x^{n-3}......... a_o[/tex]

Possible Rational Roots

=±factors of [tex]a_n[/tex]/factors of [tex]a_o[/tex]

Here in our polynomial

[tex]a_n= 5[/tex]

factors of 5 = 1 , 5

[tex]a_o=11[/tex]

factors of 11 = 1,11

Hence possible rational roots are

±factors of 5 / factors of 11

±[tex]\frac{1}{1}[/tex] , ±[tex]\frac{1}{11}[/tex] , ±[tex]\frac{5}{1}[/tex] , ±[tex]\frac{5}{11}[/tex]

Otras preguntas