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Student scores
Student Score
Tom 89
Jon 72
Sue 98
Jill 78
Zeke 62

Five students in a small class made the test scores shown in the table. What was the mean absolute deviation for the class?
A) 10.96
B) 35.44
C) 52.87
D) 79.80

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➷ mean = 399/5 = 79.8

total of data value - mean = 54.8

54.8/5 = 10.96

Your answer is A. 10.96

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homadison4

Answer:

A) 10.96

Step-by-step explanation:

First find the mean:

Add up the values to find the mean of the data set:

89 + 72 + 98 + 78 + 62 = 399

Divide 399 by 5 because there are 5 numbers in the data set:

[tex]\frac{399}{5} = 79.8[/tex]

Subtract the numbers of the data set by the mean.

89 - 79.8 = 9.2

72 - 79.8 = -7.8

98 - 79.8 = 18.2

78 - 79.8 = -1.8

62 - 79.8 = -17.8

The mean deviation is always positive so change the negatives to positives.  After that, add them up:

9.2 + 7.8 + 18.2 + 1.8 + 17.8 = 54.8

Then divide 54.8 by 5 because there are five numbers in the data set.

[tex]\frac{54.8}{5} = 10.96[/tex]

The mean deviation is 10.96

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