Answer:
No, the equation is not in quadratic form.
Step-by-step explanation:
We have [tex]x^9-5x^3+6=0[/tex],
The quadratic equations have the form [tex]ax^2+bx+c=0[/tex] with [tex]a\neq 0[/tex]
In this case we have the first term [tex]x^9[/tex] raised to the ninth, and we can see that a quadratic equation has the first term squared.
The second term [tex]5x^3[/tex] is raised to the cube, and the quadratic equation has the second term raised to one.
Then the equation [tex]x^9-5x^3+6=0[/tex] isn't a quadratic equation.
