Answer:
516
Step-by-step explanation:
So this is a problem that can be solved using sequences and series.
The formula for an arithmetic sum is:
[tex]Sn = \frac{n}{2} (2u_{1} + (n-1)d) \\[/tex]
Our n value or the number of rows is 24
Our first row or u1 is 10
And our common difference is 1 as 11-10 is 1
So:
[tex]S_{24} = \frac{24}{2} (2(10) + (24-1)1)\\\\[/tex]
[tex]S_{24} = 12(20 + 23)[/tex]
[tex]S_{24} = 516[/tex]
I believe this is the correct method to solve this problem
