Answer:
The correct answer is option D.
Explanation:
Mass of [tex]N_2O_3[/tex] = 137 g
Moles of[tex]N_2O_3[/tex]
[tex]=\frac{137.0 g}{76 g/mol}=1.8026 mole[/tex]
Number of molecules of [tex]N_2O_3[/tex]:
[tex]1.8026 moles\times N_A=1.8026 mol\times 6.022\times 10^{23} mol^{-1}=1.0855 \times 10^{24} molecules[/tex]
In 1 molecule of [tex]N_2O_3[/tex] there are two atoms of nitrogen.
Then in [tex]1.0855 \times 10^{24} molecules[/tex] of [tex]N_2O_3[/tex]:
[tex]1.0855 \times 10^{24}\times 2=2.171\times 10^{24} atoms[/tex]
The number of nitrogen atoms are [tex]2.171\times 10^{24}[/tex]
