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Simplify the rational expression.

LaTeX: \frac{x^2-4x-32}{x+4} x 2 − 4 x − 32 x + 4

LaTeX: x+8 x + 8
LaTeX: x-8 x − 8
LaTeX: -x+8 − x + 8
LaTeX: -x-8

Respuesta :

gmany

Answer:

[tex]\large\boxed{\dfrac{x^2-4x-32}{x+4}=x-8}[/tex]

Step-by-step explanation:

[tex]\dfrac{x^2-4x-32}{x+4}=\dfrac{x^2+4x-8x-32}{x+4}=\dfrac{x(x+4)-8(x+4)}{x+4}\\\\=\dfrac{(x+4)(x-8)}{x+4}\\\\\text{canceled}\ (x+4)\\\\=x-8[/tex]

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