Find the particular solution to y " = 2sin(x) given the general solution y = βˆ’2sin(x) + Ax + B and the initial conditions y of pi over 2 equals 0 and y prime of pi over 2 equals negative 2.

βˆ’2sin(x) + 2

βˆ’2sin(x) βˆ’ 2x + Ο€ + 2

βˆ’2sin(x) βˆ’ 2x + 2Ο€

βˆ’2sin(x) βˆ’ 2x + Ο€

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Answer:

hello : βˆ’2sin(x) βˆ’ 2x + Ο€ + 2

Step-by-step explanation:

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