Find the particular solution to y " = 2sin(x) given the general solution y = β2sin(x) + Ax + B and the initial conditions y of pi over 2 equals 0 and y prime of pi over 2 equals negative 2.
β2sin(x) + 2
β2sin(x) β 2x + Ο + 2
β2sin(x) β 2x + 2Ο
β2sin(x) β 2x + Ο