Answer:
x −2 0 1
y −4 1 2
dy/dx one half 0 one half
Step-by-step explanation:
Actually, it can be solved without solving the differential equation. You just put the given numbers into the given equation.
dy/dx = x/y
For (x, y) = (-2, -4), dy/dx = (-2)/(-4) = 1/2
For (x, y) = (0, 1), dy/dx = 0/1 = 0
For (x, y) = (1, 2), dy/dx = 1/2
Answer:
Step-by-step explanation:
Given that a differential equation of I order and degree is of the form
[tex]\frac{dy}{dx}=\frac{x}{y}[/tex]
Cross multiply to separate variables as
ydy = xdx
Integrate both sides to get
[tex]\frac{y^2}{2} =\frac{x^2}{2} +C\\x^2-y^2 =C'[/tex]
From the options given we find that correct one is
Cannot be found without solving the differential equation
