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A bag contains 22 red marbles, 33 green marbles, and 44 blue marbles. If we choose a marble, then another marble without putting the first one back in the bag, what is the probability that the first marble will be green and the second will be red?

Respuesta :

Answer:

[tex]\frac{11}{147}[/tex]

Step-by-step explanation:

P(green ) = [tex]\frac{33}{99}[/tex] = [tex]\frac{1}{3}[/tex]

Without replacement the total number of marbles = 98

P(red) = [tex]\frac{22}{98}[/tex] = [tex]\frac{11}{49}[/tex]

P(green and red ) = [tex]\frac{1}{3}[/tex] × [tex]\frac{11}{49}[/tex] = [tex]\frac{11}{147}[/tex]

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