Respuesta :



the answer to the question
Ver imagen meredith48034

For this case we have the following expression:

[tex]\frac {\frac {24y ^ 8} {15x ^ 5}} {\frac {8y ^ 4} {4x ^ 2}} =[/tex]

Simplifying we have:

[tex]\frac {\frac {8y ^ 8} {5x ^ 5}} {\frac {2y ^ 4} {x ^ 2}} =\\\frac {8y ^ 8 * x ^ 2} {5x ^ 5 * 2y ^ 4} =[/tex]

For power properties of the same base we have:

[tex]\frac {a ^ m} {a ^ n} = a ^ {m-n}[/tex]

So:

[tex]\frac {8 * y ^ 8 * x ^ 2} {10 * x ^ 5 * y ^ 4} =\\\frac {4} {5} * y ^ {8-4} * x ^ {2-5} =\\\frac {4y ^ 4} {5x ^ 3}[/tex]

Answer:

[tex]\frac {4y ^ 4} {5x ^ 3}[/tex]