Respuesta :
The reaction is
CaC₂(s) + 2H₂O (l) -----> Ca(OH)₂ (s) + C₂H₂ (g)
As we have data of gas ethyne (or acetylene), C₂H₂
We can calculate the moles of acetylene and from this we can estimate the mass of calcium carbide taken
the moles of acetylene will be calculated using ideal gas equation
PV =nRT
R = gas constant = 0.0821 Latm/molK
T = 385 K
V = volume = 550 L
P = Pressure = 1.25 atm
n = moles = ?
n = PV /RT = 1.25 X 550 / 0.0821 X 385 = 21.75 mol
As per balanced equation these moles of acetylene will be obtained from same moles of calcium carbide
moles of calcium carbide = 21.75mol
molar mass of CaC₂ = 40 + 24 = 64
mass of CaC₂ = moles X molar mass = 21.75 X 64 = 1392g
Answer:
The mass of calcium carbide is 1,392 grams.
Explanation:
Pressure of the ethyne gas = P = 1.25 atm
Volume of the ethyne gas = V = 550 L
Temperature of the ethyne gas = T = 385 K
Moles of ethyne gas = n
PV = nRT (ideal gas equation)
[tex]n=\frac{PV}{RT}=\frac{1.25 atm\times 550 L}{0.0821 atm L/mol K\times 385 K}=21.75 mol[/tex]
[tex]CaC_2(s) + 2 H2O (l)\rightarrow Ca(OH)_2 (s) + C_2H_2 (g)[/tex]
According to reaction , 1 mole of ethyne is obtained from 1 mole of calcium carbide.
Then 21.75 moles of ethyne will be obtained from:
[tex]\frac{1}{1}\times 21.75 mol=21.75 mol[/tex] calcium carbide.
Mass of 21.75 moles of calcium carbide:
= 21.75 mol × 64 g/mol = 1,392 g
The mass of calcium carbide is 1,392 grams.
