Days in a week n(S)=7
DAYS to not getting monday n(M)=6
probability P(M)=n(M)/n(S)
=6/7(ans)
The probability of randomly selecting a day of the week and not getting Monday will be 6 / 7.
Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.
The probability of randomly selecting a day of the week and not getting Monday will be
The total number of events will be
Total event = 7 {M, T, W, T, F, S, S}
Favorable event = 6 {T, W, T, F, S, S}
Then the probability will be
P = 6/7
More about the probability link is given below.
https://brainly.com/question/795909
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