Answer:
[tex]1.13\cdot 10^5 J[/tex]
Explanation:
The amount of work done by Devin when moving the lawn is given by:
[tex]W=Fd cos \theta[/tex]
where
F is the average force applied
d is the displacement of the lawn
[tex]\theta[/tex] is the angle between the direction of the force and the displacement
Assuming that Devin moves the lawn by applying a force parallel to the displacement, we have:
F = 75 N
d = 1.5 km = 1500 m
[tex]\theta=0^{\circ}[/tex]
Therefore, the work done is
[tex]W=(75 N)(1500 m)(cos 0^{\circ})=1.13\cdot 10^5 J[/tex]
