kimberly needs to solve the quadratic equation: x^2 + x – 2 = 2. which statement about how kimberly should solve this equation is true?

A.The quadratic formula is the only way to solve a quadratic equation.

B.The quadratic formula is a good method because this quadratic equation cannot be easily factored.

C.The quadratic formula is not a good method because you can factor the equation since -2 is divisible by 1.

D.Kimberly cannot solve this quadratic equation because it is not set equal to 0.

The statement about how kimberly should solve this equation which is true is given by: Option B.The quadratic formula is a good method because this quadratic equation cannot be easily factored.

How to find the roots of a quadratic equation?

Suppose that the given quadratic equation is

[tex]ax^2 + bx + c = 0[/tex]

Then its roots are given as:

[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]

How to find the factors of a quadratic expression?

If the given quadratic expression is of the form [tex]ax^2 + bx + c = 0[/tex],

then its factored form is obtained by two numbers alpha( α ) and beta( β) such that: [tex]b = \alpha + \beta \\ ac =\alpha \times \beta[/tex]

Then writing b in terms of alpha and beta would help us getting common factors out.

Sometimes, it is not possible to find factors easily, so using the straightforward formula for quadratic equation's roots can help out without any trial and error.

The given quadratic equation is:

[tex]x^2 + x -2 = 2[/tex]

We can rewrite it in the form [tex]ax^2 + bx + c = 0[/tex] as: [tex]x^2 + x -4 = 0[/tex]

here a = 1, b = 1 and c = -4

Thus, for factorization, we need two numbers [tex]\alpha[/tex] and [tex]\beta[/tex] such that:

[tex]b = 1= \alpha + \beta \\ ac = -4=\alpha \times \beta[/tex]

If we take integers, then 4 is multiplication of 1 and 4, or 2 and 2, none of them can add or subtract to make 1.

So, easy factors aren't possible.

Using the formula for solutions, we get:

[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \dfrac{-1 \pm \sqrt{1- 4(1)(-4)}}{2}\\\\x = \dfrac{-1 \pm \sqrt{17}}{2}[/tex]

so we see that the solutions are really so hard to end up from trial and error method.

Factors are real, and one can end up on these factors if their luck is going good, but using quadratic formula would be easy.

Thus, the statement about how kimberly should solve this equation which is true is given by: Option B.The quadratic formula is a good method because this quadratic equation cannot be easily factored.

Learn more about finding the solutions of a quadratic equation here:

https://brainly.com/question/3358603