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A bus and a car have an inelastic head-on collision. The bus has a mass of 1.5 × 103 kilograms and an initial velocity of +20 meters/second. The car has a mass of 9.5 × 102 kilograms and an initial velocity of -26 meters/second. What is their total momentum after the collision?

Respuesta :

Multiply and add

Pcar + Pbus = Ptot

Since they have an inelastic collision it means they'll stick, so

1500(20) + (950)(-26) = 5300

The total momentum is 5300 kg*m/s

Answer:

5 300 [tex]kgms^{-1}[/tex]

Explanation:

Think step:

The momentum is the product of mass an velocity, that is P = mv

The law of conservation of momentum states that for an elastic collision, the sum of the momenta is zero. That is: ∑P = mv₁ + mv₂ + mv₃ + mv...

So we add the momenta like this:

mass of bus = 1.5 × 10³ kg

velocity of the bus = + 20 m/s

mass of car = 9.5 × 10² kg

velocity of car = - 26 m/s

The total momentum = [tex]m_{car} v_{car} + m_{bus} v_{bus} \\= 9.5*10^{2}* (-26) + 1.5*10^{3}*(20) \\ = -24700+30000\\ = 5 300 kg[/tex]