Answer:
[tex] x = 3 + 2\sqrt{2} ~~~ or ~~~ x = 3 - 2\sqrt{2} [/tex]
Step-by-step explanation:
[tex] x^2 - 6x + 1 = 0 [/tex]
[tex] x^2 - 6x = -1 [/tex]
[tex] x^2 - 6x + 9 = -1 + 9 [/tex]
[tex] (x - 3)^2 = 8 [/tex]
[tex] x - 3 = \pm \sqrt{8} [/tex]
[tex] x - 3 = 2\sqrt{2} ~~~ or ~~~ x - 3 = -2\sqrt{2} [/tex]
[tex] x = 3 + 2\sqrt{2} ~~~ or ~~~ x = 3 - 2\sqrt{2} [/tex]