Answer:
The surface area of the model pyramid is [tex]451\ in^{2}[/tex]
Step-by-step explanation:
we know that
The surface area of the pyramid is equal to
[tex]SA=B+LA[/tex]
where
B is the area of the base of the pyramid
LA is the lateral surface of the pyramid
Find the area of the base B
[tex]B=11^{2}=121\ in^{2}[/tex] -----> is a square
Find the lateral surface area of the pyramid LA
we know that
The lateral surface area is equal to the area of its four triangular faces
[tex]LA=4[\frac{1}{2}(11)(15)]=330\ in^{2}[/tex]
Find the surface area of the pyramid
Substitute the values
[tex]SA=121+330=451\ in^{2}[/tex]
