Answer:
2.00 J/g.°C
Explanation:
To solve this problem, we can use the relation:
Q = mcΔT,
Where, Q is the amount of heat needed to raise the temperature of the substance (J).
m is the mass of the substance (g).
c is the specific heat capacity of the substance (J/g.°C).
ΔT is the temperature difference (ΔT = final T - initial T).
As clear from the relation; ΔT = Q / mc,
∵ ΔT ∝ 1/c,
The temperature difference is inversely proportional to the specific heat of the substance.
∴ The substance that will have least increase in temperature will be that has the highest specific heat capacity (2.00 J/g.°C).
Answer:
The substance with least increase in temperature will have highest value of specific heat and that is 2.00 J/g °C.
Explanation:
[tex]Q=m\times c\Delta T[/tex]
Q = heat released or absorbed
m = mass of the substance
c = Specific heat of the substance
ΔT = change in temperature
[tex]c=\frac{Q}{m\Delta T}[/tex]
The specific heats of the four substances are 1.01 J/g °C, 0.38 J/g °C, 0.45 J/g °C, and 2.00 J/g °C.
As we can see that from the above equation , specific heat of the substance is inversely linked to change in temperature.
[tex]c\propto \frac{1}{\Delta T}[/tex]
If all the substance absorbed Q amount of heat energy:
So, the substance with least increase in temperature will have highest value of specific heat and that is 2.00 J/g °C.
