Respuesta :

carlosego

Answer: OPTION A.

Step-by-step explanation:

First you must calculate the lenght of the side DF by applying the Pythagorean theorem, as following:

[tex]DE=\sqrt{10^{2}-8^{2}}=6[/tex]

Now you can find sin(E) as you can see below:

[tex]sin\alpha=opposite/hypotenuse[/tex]

Where:

[tex]\alpha=E\\opposite=DF=6\\hypotenuse=EF=10[/tex]

Then:

 [tex]sin(E)=6/10[/tex]

[tex]sin(E)=3/5[/tex]

imlittlestar

Answer:

The correct answer is option A. 3/5

Step-by-step explanation:

Pythagorean theorem:-

Hypotenuse² = Base² + Height²

Trigonometric ratio:-

Sin(∅) = Opposite side / Hypotenuse

It is given a right angled triangle DEF.

DE = 8 and FE = 10

To find the length of DF

Hypotenuse² = Base² + Height²

FE² = DF² + DE²

DF² = FE² - DE² =  10² - 8² = 100 - 64 = 36

DF =√36 = 6

To find Sin(E)

Sin(E) = Opposite side / Hypotenuse = DF/EF = 6/10 =3/5

Sin(E) = 3/5

The correct answer is option A. 3/5

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