Compute the measures of center for both the boys and girls data. Describe their differences. Use the terms mean and median to justify your answer.

The Board:

Boys: 50, 32, 15, 56, 81, 50, 18, 81, 22, 55

Girls: 75, 41, 25, 22, 7, 0, 43, 12, 45, 70

Respuesta :

Answer:boys: median=50, mean=46

Girls: median= 33, mean=34

Step-by-step explanation:

Mean is the average. Median is the middle number. Both groups had 10 scores. Boys ranged from 15-81. Girls from 0-75; their mean & median would be less because their scores are less.

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The mean and median of boys and girls should be 50, 46, and 33, 34.

Calculation of mean and median

For boys:

First we have to write in a sequence manner

15,18,22,32,50,50,55,56,81,81

So here the median should be 50

And, the mean should be [tex]= (15+ 18+ 22+ 32+ 50+ 50+ 55+ 56+ 81+ 81) \div 10[/tex]

= 46

For girls:

First we have to write in a sequence manner

0,7,12,22,25,41,43,45,70,75

So here the median should be [tex]= (25 + 41) \div 2[/tex] = 33

And, the mean should be [tex]= (0+ 7+ 12+ 22+ 25+ 41+ 43+ 45+ 70+ 75) \div 10[/tex]

= 34

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