PART A)
From gravitational force formula we know that
[tex]F = \frac{Gm_1m_2}{r^2}[/tex]
now we have
[tex]m_1 = 6.4 \times 10^{23} kg[/tex]
[tex]m_2 = 0.48 \times 10^{15} kg[/tex]
[tex]r = 23460 km[/tex]
now we have
[tex]F = \frac{6.67\times 10^{-11}(6.4\times 10^{23})(0.48\times 10^{15})}{(23460\times 10^3)^2}[/tex]
[tex]F = 3.72\times 10^{13} N[/tex]
Part B)
again from same formula as we used above to find the force
[tex]F = \frac{Gm_1m_2}{r^2}[/tex]
now we have
[tex]m_1 = 6.4 \times 10^{23} kg[/tex]
[tex]m_2 = 800 kg[/tex]
[tex]r = (3396 + 400) = 3796 km[/tex]
now we have
[tex]F = \frac{6.67\times 10^{-11}(6.4\times 10^{23})(800)}{(3796\times 10^3)^2}[/tex]
[tex]F = 2370 N[/tex]
PART C)
here in circular orbit the speed of the satellite will remain the same always
So here kinetic energy of satellite will always remain same
There is no change in kinetic energy of satellite
Part d)
Since satellite is revolving in circular orbit so the distance will always remain the same
As well as the two masses is also constant
So here the gravitational force between them is always same and it will not change
a) According to Newton's law of gravitation,
[tex]F=GM_1M_2/R^2= 3.72\cdot 10^13[/tex] N
b) [tex]F=Gm_1m_2/(r+R)^2= 2369.97 [/tex] N
c) It remains the same because the velocity doesn't change.
d) Also constant because its orbit is circular.
