Use the quadratic formula to find both solutions to the quadratic equation given below 3x^2-x+6=0

Hello from MrBillDoesMath!
Answer:
Choice E and F
Discussion:
From the quadratic formula with a = 3, b = -1, and c = 6
x = ( -b +\- sqrt(b^2 - 4ac) ) / (2a) => substitute in a,b,c from above
x = ( -(-1) +\- sqrt((-1)^2 - 4(3)(6)) / (2*3) => discriminant = 1 - 72 = -71)
x = ( 1 +\- sqrt(-71))/ 6
which are choices E and F
Thank you,
MrB
Answer:
Choices E and F are the answers.
Step-by-step explanation:
We have given a quadratic equation.
3x²-x+6 = 0
We have to solve given equation by quadratic formula.
x = (-b±√b²-4ac) / 2a is quadratic formula to solve this.
In given equation, a = 3 , b = -1 and c = 6
Putting the values of a, b and c in above formula, we have
x = (-(-1)±√(-1)²-4(3)(6) ) / 2(3)
x = (1±√1-72) / 6
x = (1±√-71) / 6
x = 1+√-71) / 6 and x = 1-√-71 / 6
Hence, the solutions are choices E and F.