Answer:
Part A) The measure of the other two acutes angles are [tex]=67.06\°[/tex] and [tex]22.94\°[/tex]
Part B) The side length of the other leg is equal to [tex]54.33\ units[/tex]
Step-by-step explanation:
Part A)
see the attached figure to better understand the problem
we know that
In the right triangle ABC
[tex]cos(A)=\frac{AB}{AC}[/tex]
substitute the values
[tex]cos(A)=\frac{23}{59}[/tex]
[tex]A=arccos(\frac{23}{59})=67.06\°[/tex]
Remember that
[tex]A+C=90\°[/tex] -------> by complementary angles
[tex]C=90\°-67.06\°=22.94\°[/tex]
Part B)
Applying the Pythagoras Theorem
[tex]CB^{2}=AC^{2}-AB^{2}[/tex]
substitute
[tex]CB^{2}=59^{2}-23^{2}[/tex]
[tex]CB^{2}=2,952[/tex]
[tex]CB=54.33\ units[/tex]