Answer:
velocity of combined objects is 6 m/s
Explanation:
As per law of conservation of momentum
total momentum before collision = total momentum after collision
since the two objects sticks together after collision so we will have
[tex]m_1v_{1i} + m_2v_{2i} = (m_1 + m_2) v[/tex]
Now plug in all values in it
[tex]300(10) + 100(-6) = (300 + 100) v[/tex]
[tex]3000 - 600 = 400(v)[/tex]
[tex]2400 = 400 v[/tex]
[tex]v = 6 m/s[/tex]
so the missing value in the table is velocity which is 6 m/s
