Answer:
a) Third Term = 19
b) Term to Term rule = Subtract 13 and then Divide by 6
Step-by-step explanation:
a)
Since first term is -2, so according to rule, second term is:
second term = [tex]-2(6)+13\\=-12+13\\=1[/tex]
Now, finding the third term with the rule:
[tex]1(6)+13\\=6+13\\=19[/tex]
Third Term = 19
b)
The first 3 terms of the sequence is -2, 1, 19 ...
If reversed, it is:
19, 1, -2 ....
The rule will also be reversed. So it will be to subtract 13 and then divide by 6.
The third term of the given sequence is 19.
Term to term rule when the sequence -2, 1, 19..... is reversed will be [tex]\frac{a-13}{6}[/tex]
The sequence is a particular order in which related things follow each other.
It is given that
The term to term rule of the sequence is [tex]6a+13[/tex], where a is the first term
First-term a = -2
Second term b will be -2*6+13 = 1
The rule for the third term will be [tex]6b+13[/tex], where b will be the second term.
So third term will be 6*1 + 13 = 19
So, the sequence will be -2, 1, 19........
If the order of the above sequence is reversed, the new sequence will be 19, 1, -2........
If we subtract 13 from first term 19 and then divide by 6 we will get 1 which is the second term of the new sequence 19, 1, -2........
So a new term to term sequence rule will be [tex]\frac{a-13}{6}[/tex] where a is the first term.
Therefore, The third term of the given sequence is 19.
Term to term rule when the sequence -2, 1, 19..... is reversed will be [tex]\frac{a-13}{6}[/tex]
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