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What equation does the graph of system of equations solve?

a. x2 − 2x − 1 = −x2 + 3
b. x2 − 2x + 3 = x2 − x + 1
c. −x2 − 2x + 2 = 2x2 − x − 2
d. −x2 − 2x + 1 = 2x2 − x + 2

Ten points!

What equation does the graph of system of equations solve a x2 2x 1 x2 3 b x2 2x 3 x2 x 1 c x2 2x 2 2x2 x 2 d x2 2x 1 2x2 x 2 Ten points class=

Respuesta :

sqdancefan

Answer:

  a.  x^2 − 2x − 1 = −x^2 + 3

Step-by-step explanation:

The red curve in the figure is described by 3-x^2. The only answer choice that includes that expression is choice a.

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The red curve is your basic y=x^2 curve reflected across the x-axis (y=-x^2) and shifted up 3 (y=-x^2+3).

Both curves go through the point that is 1 over and 1 up (or down) from the vertex, so the vertical scale factor is 1. That is, any choice with 2x^2 in it will not be an answer.

Answer:

The required Equation is [tex]x^2-2x-1=-x^2+3[/tex]

Step-by-step explanation:

Given : The graph of two equations intersecting each other at (-1,2) and (2,-1).

To find : What equation does the graph of system of equations solve?

Solution :

To find the equations we have to put the points if the equation satisfied then it is the required equation.

a) [tex]x^2-2x-1=-x^2+3[/tex]

Let [tex]y_1=x^2-2x-1[/tex] and [tex]y_2=-x^2+3[/tex]        

Put (-1,2)

[tex]2=(-1)^2-2(-1)-1[/tex] and [tex]2=-(-1)^2+3[/tex]        

[tex]2=1+2-1[/tex] and [tex]2=-1+3[/tex]        

[tex]2=2[/tex] and [tex]2=2[/tex]

Put (2,-1)

[tex]-1=(2)^2-2(2)-1[/tex] and [tex]-1=-(2)^2+3[/tex]        

[tex]-1=4-4-1[/tex] and [tex]-1=-4+3[/tex]        

[tex]-1=-1[/tex] and [tex]-1=-1[/tex]        

As the equation satisfying the points.

Therefore, The required Equations i [tex]x^2-2x-1=-x^2+3[/tex]