Answer:
The quotient is [tex]\frac{x(2x-3)}{7}[/tex] answer (D)
Step-by-step explanation:
[tex]\frac{2x-3}{x}[/tex] ÷ [tex]\frac{7}{x^{2} }[/tex]
In division with fractions we reverse the fraction after division sign and change division sign to multiplication sine
[tex]\frac{2x-3}{x}[/tex] × [tex]\frac{x^{2} }{7}[/tex]
[tex]\frac{2x-3}{1}[/tex] × [tex]\frac{x}{7}[/tex]
[tex]\frac{x(2x-3)}{7}[/tex]
