c
2
−
64
Rewrite
as
8
.
Since both terms are perfect squares, factor using the difference of squares formula,
a
b
=
(
+
)
where
and
[tex]Answer: \\ {c }^{2} - 64 = (c - 8)(c + 8) \\ \Rightarrow GCF:c + 8[/tex]
