Hey there!:
Molar mass Ca(NO2)2 = 132.089 g/mol
Mass of solute = 120 g
Number of moles:
n = mass of solute / molar mass
n = 120 / 132.089
n = 0.0009084 moles of Ca(NO2)2
Volume in liters of solution :
240 mL / 1000 => 0.24 L
Therefore:
Molarity = number of moles / volume of solution
Molarity = 0.0009084 / 0.24
Molarity = 0.003785 M
Hope that helps!
120 grams of calcium nitrite is dissolved in a 240 mL solution, then the molarity of the solution is 3.75M.
Molarity (M) of any solution is define as the number of moles (n) of solute present in per liter (V) of the solution, i.e.
M = n/V
And moles will be calculated as:
n = W/M, where
W = given mass of calcium nitrite = 120g
M = molar mass of calcium nitrite = 132g/mol
Moles of calcium nitrite = 120 / 132 = 0.90 mol
Volume of solution = 240mL = 0.24L
Molarity of solution = 0.90/0.24 = 3.75M
Hence required molarity is 3.75M.
To know more about molarity, visit the below link:
https://brainly.com/question/26232880
