Respuesta :

carlosego

Answer: Option b.

Step-by-step explanation:

 1. You can rewrite it as following:

[tex]\lim_{x\to \ -6} 2[/tex]

This means that you must substitute x=-6 into the limit. There is not x, then the function is always equal to 2, no matter the value of x.

[tex]\lim_{x\to \ -6} 2=2[/tex]

 [tex]\lim_{x\to \ -6} 1[/tex]

 This means that you must substitute x=-6 into the limit. There is not x, then the function is always equal to 1, no matter the value of x.

[tex]\lim_{x\to \ -6} 1=1[/tex]

2. Then:

[tex]\lim_{x\to \ -6} (f/g)(x)=2/1=2[/tex]

3. The answer 2.

kudzordzifrancis

Answer:

b. 2

Step-by-step explanation:

Given that;

[tex]\lim_{x \to -6} f(x)=2[/tex] and [tex]\lim_{x \to -6} g(x)=1[/tex]

Use the properties of limits;

[tex] \lim_{x \to -6} (\frac{f}{g})(x)= \lim_{x \to -6} (\frac{f(x)}{g(x)})[/tex]

[tex]\lim_{x \to -6} (\frac{f}{g})(x)= (\frac{\lim_{x \to -6}f(x)}{\lim_{x \to -6}g(x)}) [/tex]

This implies that;

[tex]\lim_{x \to -6} (\frac{f}{g})(x)= \frac{2}{1}[/tex]

[tex]\lim_{x \to -6} (\frac{f}{g})(x)=2[/tex]

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