Answer:
[tex]I=\frac{13xr}{1,200}[/tex]
Step-by-step explanation:
we know that
The simple interest formula is equal to
[tex]I=P(rt)[/tex]
where
I is the Simple interest Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal form
t is Number of Time Periods in years
in this problem we have
[tex]t=(13/12)\ years\\ P=\$x\\r=(r/100)[/tex]
substitute in the formula above
[tex]I=x(r/100)(13/12)[/tex]
[tex]I=\frac{13xr}{1,200}[/tex]
