Kor4k
contestada

Plz help asap

Use the identity, tan[tex]tan0 = \frac{sin 0}{cos 0}[/tex] to find [tex]tan 0[/tex] if...


a) [tex]sin 0 = \frac{3}{5}[/tex] and [tex]cos0 = \frac{4}{5}[/tex]

b) [tex]cos0=\frac{5}{13}[/tex] and [tex]sin0=\frac{12}{13}[/tex]

Respuesta :

Answer:

let the angle be α, i cant input that one

a) tanα=[tex]\frac{3}{4}[/tex]

b) tanα=[tex]\frac{12}{5}[/tex]

Step-by-step explanation:

a) tanα=[tex]\frac{sin\alpha }{cos\alpha }[/tex]

           =[tex]\frac{\frac{3}{5} }{\frac{4}{5} }[/tex]

           =[tex]\frac{3}{4}[/tex]

b) tanα=[tex]\frac{sin\alpha }{cos\alpha }[/tex]

           =[tex]\frac{\frac{12}{13} }{\frac{5}{13} }[/tex]

           =[tex]\frac{12}{5}[/tex]