Answer:
[tex]\large\boxed{Q1.\ x>1}\\\boxed{Q2.\ x>1}\\\boxed{Q3.\ x\leq-3}[/tex]
Step-by-step explanation:
[tex]Q1.\\7x+3>10\qquad\text{subtract 3 from both sides}\\\\7x+3-3>10-3\\\\7x>7\qquad\text{divide both sides by 7}\\\\\dfrac{7x}{7}>\dfrac{7}{7}\\\\\boxed{x>1}\\\\Q2.\\-3+5x<7x-5\qquad\text{add 3 to both sides}\\\\-3+3+5x<7x-5+3\\\\5x<7x-2\qquad\text{subtract 7x from both sides}\\\\5x-7x<7x-7x-2\\\\-2x<-2\qquad\text{change the signs}\\\\2x>2\qquad\text{divide both sides by 2}\\\\\dfrac{2x}{2}>\dfrac{2}{2}\\\\\boxed{x>1}[/tex]
[tex]Q3.\\-2x+5\geq3x+20\qquad\text{subtract 5 from both sides}\\\\-2x+5-5\geq3x+20-5\\\\-2x\geq3x+15\qquad\text{subtract 3x from both sides}\\\\-2x-3x\geq3x-3x+15\\\\-5x\geq15\qquad\text{change the signs}\\\\5x\leq-15\qquad\text{divide both sides by 5}\\\\\boxed{x\leq-3}[/tex]
