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Consider the reaction: so2cl2(g)⇌so2(g)+cl2(g) kp=2.91×103 at 298 k in a reaction at equilibrium, the partial pressure of so2 is 0.156 atm and that of cl2 is 0.370 atm . part a what is the partial pressure of so2cl2 in this mixture?

Respuesta :

superman1987

Answer:

1.98 x 10⁻⁵ atm.

Explanation:

  • For the reaction: SO₂Cl₂(g) ⇌ SO₂(g) + Cl₂(g), Kp = 2.91 x 10³.

∵ Kp = (PSO₂)(PCl₂)/(PSO₂Cl₂).

PSO₂ = 0.156 atm, PCl₂ = 0.370 atm.

∴ 2.91 x 10³ = (0.156 atm)(0.370 atm)/(PSO₂Cl₂)

∴ (PSO₂Cl₂) = (0.156 atm)(0.370 atm)/(2.91 x 10³) = 1.98 x 10⁻⁵ atm.